Question

Plssssss help!!! On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles, find the total distance traveled in the two days.

Answer 1

The total distance traveled in two days would be 380 miles.

Let's see how we calculate the distance.

• Distance is calculated by multiplying speed with time. So,
• D = S * T
• S = D ÷ T

Given that,

Speed on first day = 40 mph

Since,

Speed = Distance/Time

∵ 40 = $d_{1}$/$T_{1}$   ...(i)

Speed on the second day = 60 mph

Distance traveled =  $d_{1}$ - 20

Time taken = $T_{1}$ - 2

Since,

Speed = Distance/Time

∵ 60 = ($d_{1}$ - 20)/ ($T_{1}$ - 2) ...(ii)

As we know,

Total distance = $d_{1} + d_{2}$

=  $d_{1}$ + $(d_{1} - 20)$

= 2$d_{1}$ - 20  ...(iii)

From (i), we can deduce that,

$d_{1}$ = 40$T_{1}$

$T_{1}$ = $d_{1}$/40

Now, by putting the values of $d_{1}$ and $T_{1}$  in equation (ii), we get

60 = ($d_{1}$ - 20)/ ($T_{1}$ - 2)

⇒ $d_{1}$ - 20 = 60($T_{1}$ - 2)

⇒ $d_{1}$ - 20 = 60$T_{1}$ - 120

⇒ $d_{1}$ - 20 = 60 * (

⇒ $d_{1}$ = 3

⇒ $d_{1}$ - 3

⇒ - $d_{1}$/2 = -100

∵ $d_{1}$ = 200

By substituting the value of $d_{1}$ in equation (iii),

Total distance = 2$d_{1}$ - 20

= 2(200) - 20

= 400 - 20

= 380 miles

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