Question

A mass of 5 kg is suspended by a rope of length 2 m from the ceiling. A force of 45 N in the horizontal direction is applied at the midpoint R of the rope, as shown. What is the angle the rope makes with the vertical in equilibrium? (Take g = 10 ms-2). Neglect the mass of the rope.

Answer 1

Answer:

Explanation:

For horizontal equilibrium-

T  

3

​  

=T  

1

​  

sinθ

For vertical equilibrium-

T  

2

​  

=T  

1

​  

cosθ

Taking ratios-

T  

2

​  

 

T  

3

​  

 

​  

=tanθ

And for equilibrium of body T  

2

​  

=5kgwt=5×10=50N

⟹tanθ=  

6

5

​  

 

or θ=tan  

−1

 

6

5

​