Question

"A parabola has the equation y=3x^2+ 6x- 12 . What are the coordinates of the vertex? (You must solve by factoring)!!!!!" I NEED THE ANSWER TO THIS FAST WITH STEPS I'm a grade 10 academic student by the way

Answer 1

y = 3x ^ 2 + 6x- 12  

(a=3; b=6; c= -12)

• Ta có Δ=b^2 -4ac

             = 6^2 -4*3*( -12)

             =180

• X= (-b+√Δ)/2a

              ≈ 3.2

• X= (-b-√Δ)/2a

 ≈ -3.2

Khi đó: y= 948/25

       Và: y= -12/25

Vậy : A(3.2: 948/25)

       B(-3.2; -12/25)

Step-by-step explanat bion :