Answer:
Step-by-step explanation:
[tex]a^{m}* a^{n}=a^{m+n}\\\\\\(\frac{-1}{2})^{-19}*(\frac{-1}{2})^{8}=(\frac{-1}{2})^{-2x +1}\\\\(\frac{-1}{2})^{-19+8}=(\frac{-1}{2})^{-2x+1}\\\\\\(\frac{-1}{2})^{-11}=(\frac{-1}{2})^{-2x+1}[/tex]
As bases are equal in boht sides, we can compare the exponents.
-2x + 1 = -11
Subtract 1 form both sides
-2x = -11 - 1
-2x = -12
Divide both sides by -2
x = -12/-2
x = 6
