Respuesta :

ct4512

Answer:

x=[tex]\frac{3}{2}[/tex] and x=[tex]\frac{1}{6}[/tex]

Step-by-step explanation:

[tex]\sqrt{36x^2-60x+25}=4[/tex]

=> [tex]\sqrt{36x^2-60x+25}^{2} =4^{2}[/tex]

=> [tex]{36x^2-60x+25}=16[/tex]

=> [tex]36x^2-60x+25-16=16-16[/tex]

=> [tex]36x^2-60x+9=0[/tex]

=> [tex]x_{1,\:2}=\frac{-\left(-60\right)\pm \sqrt{\left(-60\right)^2-4\cdot \:36\cdot \:9}}{2\cdot \:36}\\\\\sqrt{\left(-60\right)^2-4\cdot \:36\cdot \:9}=48[/tex]

=> [tex]x_{1,\:2}=\frac{-\left(-60\right)\pm \:48}{2\cdot \:36}[/tex]

=>[tex]x_{1} = \frac{-\left(-60\right)+48}{2\cdot \:36}\\\\x_{1}=\frac{60+48}{2\cdot \:36}\\\\x_{1}=\frac{108}{72} \\\\\\x_{1}=\frac{3}{2}\\[/tex]

=> [tex]x_{2}=\frac{-\left(-60\right)-48}{2\cdot \:36}\\\\x_{2} =\frac{60-48}{2\cdot \:36}\\\\x_{2}=\frac{12}{2\cdot \:36}\\\\\x_{2}=\frac{12}{72}\\\\x_{2}=\frac{1}{6}[/tex]

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