Solve the quadratic equation by completing the square.

Answer:
[tex] {k}^{2} + 2k + \frac{15}{2} = 0 \\ {k}^{2} + 2k + 1 = - \frac {15}{2} + 1 \\ {k + 1}^{2} = - \frac{13}{2} \\ k + 1 = - \sqrt{ \frac{13}{2} } \\ k = 1 + or - - \sqrt{ \frac{13}{2} } [/tex]