Respuesta :

We know

[tex]\boxed{\sf tan\Theta=\dfrac{P}{B}}[/tex]

[tex]\\ \sf\longmapsto tan58=\dfrac{22}{x}[/tex]

[tex]\\ \sf\longmapsto 1.6=\dfrac{22}{x}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{22}{1.6}[/tex]

[tex]\\ \sf\longmapsto x=13.7[/tex]

[tex]\\ \sf\longmapsto x\approx 14[/tex]

Answer: x= 13.8

Step-by-step explanation:

Let the reference angle be 58

tan58 = p/b

or, tan 58 = 22/x

or, x = 22/tan58

or, x = 13.7471

so, x = 13.8

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