Answer:
[tex]P(x = 1) = 0.33[/tex]
[tex]P(y = 2) = 0.42[/tex]
Step-by-step explanation:
Given
y
x [tex]\begin{array}{cccc}P(x,y) & {0} & {1} & {2} & {0} & {0.10} & {0.03} & {0.02} & {1} & {0.06} & {0.20} & {0.07} & {2} & {0.05} & {0.14} & {0.33}\ \end{array}[/tex]
Solving (a)
[tex]P(x = 1)[/tex]
To do this, we simply add all data where x = 1
So, we have:
[tex]P(x = 1) = P(x=1|y=0) + P(x=1|y=1) + P(x=1|y=2)[/tex]
[tex]P(x = 1) = 0.06 + 0.20 + 0.07[/tex]
[tex]P(x = 1) = 0.33[/tex]
Solving (b)
[tex]P(y = 2)[/tex]
To do this, we simply add all data where y = 2
So, we have:
[tex]P(y = 2) = P(x=0|y=2) + P(x=1|y=2) + P(x=2|y=2)[/tex]
[tex]P(y = 2) = 0.02 + 0.07 + 0.33[/tex]
[tex]P(y = 2) = 0.42[/tex]