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Enter the equation of the line in slope-intercept form. Slope is -1/2, and (-9,4) is on the line. The equation of the line is y=

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Answer:

[tex]y=\displaystyle-\frac{1}{2}x-\displaystyle\frac{1}{2}[/tex]

Step-by-step explanation:

Hi there!

Slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0)

1) Plug in the slope (m)

We're given that the slope is [tex]\displaystyle-\frac{1}{2}[/tex]. In [tex]y=mx+b[/tex], replace m with [tex]\displaystyle-\frac{1}{2}[/tex]:

[tex]y=\displaystyle-\frac{1}{2}x+b[/tex]

2) Determine the y-intercept (b)

[tex]y=\displaystyle-\frac{1}{2}x+b[/tex]

We're given the point (-9,4). Plug this point into the equation as [tex](x,y)[/tex] and solve for b:

[tex]4=\displaystyle-\frac{1}{2}(-9)+b\\\\4=\displaystyle\frac{9}{2}+b[/tex]

Subtract [tex]\displaystyle\frac{9}{2}[/tex] from both sides to isolate b:

[tex]4-\displaystyle\frac{9}{2}=\displaystyle\frac{9}{2}+b- \displaystyle\frac{9}{2}\\\\\displaystyle-\frac{1}{2} = b[/tex]

Therefore, the y-intercept is [tex]\displaystyle-\frac{1}{2}[/tex]. Plug this back into [tex]y=\displaystyle-\frac{1}{2}x+b[/tex] as b:

[tex]y=\displaystyle-\frac{1}{2}x+(\displaystyle-\frac{1}{2})\\\\y=\displaystyle-\frac{1}{2}x-\displaystyle\frac{1}{2}[/tex]

I hope this helps!

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