Question

Subtract (4x2 - x + 6) from (3x2 + 5x - 8).

A:7x^2 + 6x - 14

B:-x^2 + 4x + 2

C:7x^2 + 4x - 2

D:-x^2 + 6x - 14

Answer 1

Step-by-step explanation:

$(4x^2-x+6)-(3x^2+5x-8)=4x^2-x+6-3x^2-5x+8$

By simplifying the right side of the equation, we come up with

$x^2+6x-14$, or D