Question

The triangle on the grid will be translated two units down.

On a coordinate plane, triangle A B C has points (2, 1), (0, negative 1), (2, negative 1).

Which shows the triangle when it is translated two units down?
On a coordinate plane, triangle A prime B prime C prime has points (0, negative 1), (0, negative 3), (2, negative 3).
On a coordinate plane, triangle A prime B prime C prime has points (0, 1), (negative 2, negative 1), (0, negative 1).
On a coordinate plane, triangle A prime B prime C prime has points (2, negative 1), (2, negative 3), (0, negative 3).
On a coordinate plane, triangle A prime B prime C prime has points (2, negative 1), (2, negative 3), (0, negative 1).

Answer 1

Given:

The vertices of the triangle ABC are A(2, 1), B(0,-1), C(2, -1).

To find:

The vertices of the image of triangle ABC if ABC is translated two units down.

Solution:

It is given that the triangle ABC is translated two units down. So, the rule of translation is:

$(x,y)\to (x,y-2)$

Using this rule, we get

$A(2,1)\to A'(2,1-2)$

$A(2,1)\to A'(2,-1)$

Similarly,

$B(0,-1)\to B'(0,-1-2)$

$B(0,-1)\to B'(0,-3)$

And,

$C(2.-1)\to C'(2,-1-2)$

$C(2.-1)\to C'(2,-3)$

The vertices of the image are A'(2,-1), B'(0,-3), C'(2,-3).

Therefore, the correct option is C.

Answer 2

Answer:

C.

Step-by-step explanation: