Answer:
9.97×10⁻⁴ atm
Explanation:
Applying,
PV = nRT............... Equation 1
Where P = pressure, V = volume, n = number of moles of air, R = molar gas constant, T = Temperature.
make P the subject of the equation
P = nRT/V............ Equation 2
From the question,
Given: V = (11×12×8) ft³ = 1056 ft³ = (1056×28.3168) = 29902.5 L, T = 25°C = (25+273) = 298 K, n = 35.41/29 = 1.22 mole
Constant: R = 0.082 atm.L/K.mol
Substitute these values into equation 2
P = 1.22×0.082×298/29902.5
P = 9.97×10⁻⁴ atm
