Question

A small emergency generator supplies 432 000 000 J of electrical energy in twenty-four hours. What is the average power output of the generator?
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Answer 1

Answer:

P = 5 kW

Explanation:

Given that,

Electrical energy = 432 000 000 J

Time, t = 24 h = 86400 s

We need to find the power output of the generator. We know that,

Power = work done/time

So,

$P=\dfrac{432 000 000}{86400}\\\\P=5000\ W$

or

P = 5 kW

So, the power output of the generator is 5 kW.