Question

QUICK 20pts!!!! 1. In a certain country, the probability that a baby that is born is a boy is 0.52 and the probably that a baby that is born is a girl is 0.48. A family has two children. If X is the number of girls born to a family, find the probability that the family has 0, 1, or 2 girls. (a) Draw a tree diagram showing the possibilities for each outcome. (b) Create the binomial distribution table for . Show all your work.

Answer 1

(a) i aint drawing a tree but basically, if left means a boy is born and right means a girl is born, the far left result (both boys) will happen with probability $(0.52)^2$, the two middle results (one boy and one girl) will both happen with probablility $0.48 \cdot 0.52$, and the far right result (both girls) will happen with probability $(0.48)^2$.

(b) binomial distribution table for what...?

Answer 2

Answer:

a)

Probability of 2B is (0.52)(0.52) = 0.2704.

Probability of BG is (0.52)(0.48) = 0.2496

Probability of GB is the same as the probability of BG, so it is 0.2496.

Probability of 2G is (0.48)(0.48) = 0.2304.

b)

Number of girls born:

Table for p(x)

For zero girls and 2 boys, it is 0.2704.

For 1 girl and 1 boy, it is 0.4992.

For 2 girls, it is 0.2304.

Step-by-step explanation: