Question

IN C++ PLEASE!!! Read integers from input and store each integer into a vector until -1 is read. Do not store -1 into the vector. Then, output all values in the vector that are greater than zero in reverse order, each on a new line.

Ex: If the input is -19 34 -54 65 -1, the output is:

65
34

#include
#include
using namespace std;

int main() {

/* Your solution goes here */

return 0;
}

Answer 1

#include
#include
using namespace std;

int main(){

int input[] = {-19, 34, -54, 65, -1};
std::vector voutput:
std::vector vinput (input, input + sizeof(input) / sizeof(int) );

for (std::vector::iterator it = vinput.begin(); it != vinput.end(); ++it)
if(*it > 0) voutput.insert(voutput.begin(), *it);
for(std::vector::iterator it = voutput.begin(); it < voutput.end(); ++it)
std::cout << *it << ‘\n’ ;

return 0;
}

Answer 2

The program is an illustration of vectors; vectors are data structures that are used to hold multiple values in one variable name

The main program

The program written in C++, where comments are used to explain each action is as follows:

#include <iostream>

#include <vector>

using namespace std;

int main(){

   //This declares the vector

   vector<int> nums;

   //This declares an integer variable

   int num;

   //Thie gets the first input

   cin>>num;

   //This loops is repeated until the user enters -1

   while(num != -1){

       nums.push_back(num);

       cin>>num; }  

   //This iterates through the vector

   for (auto i = nums.begin(); i != nums.end(); ++i){

       //This checks if the current element is above 1

       if(*i > 0){

           //If yes, the element is printed

           cout << *i <<endl;

       }      

   }

       return 0;

}

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