Question

Find the TWO integers whos product is -12 and whose sum is 1
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Answer 1

Answer: -3, 4

Step-by-step explanation:

• Integer #1 = x
• Integer #2 = y

x · y = -12

x + y = 1 ⇒ y = 1 - x

Bring the y-value(1 - x) into x · y = -12:

$x(1 - x) = -12 \\x-x^{2}=-12\\-x^{2}+x+12=0\\-(x^{2}-x-12)=0\\(x+3)(x-4)=0\\x=-3,x=4$

Bring the x-values into y = 1 - x and see if the values multiply to -12:

x = -3 ⇒ 1 - (-3) = 4 ⇒ 4 * -3 = -12

x = 4 ⇒ 1 -4 = -3 ⇒ -3 * 4 = -12