Answer:
L = 0.16 yd, W = 0.22 yd
Step-by-step explanation:
Dimensions of play ground 23/147 yd x 3/14 yd
reducing factor 2/147
Let the original length is L.
[tex]L - \frac{2L}{147} = \frac{23}{147}\\\\L\frac{143}{147} = \frac{23}{147}\\\\L=\frac{23}{143} yd[/tex]
L = 0.16 yd
Let the width is W.
[tex]W - \frac{2W}{147} = \frac{3}{14}\\\\W\frac{143}{147} = \frac{3}{14}\\\\W=0.22 yd[/tex]