Question

Assuming the atmospheric pressure is 1 atm at sea level, determine the atmospheric pressure at Badwater (in Death Valley, California) where the elevation is 86.0 m below sea level.

Answer 1

Answer:

Atmospheric pressure at Badwater is 1.01022 atm

Explanation:

Data given:

1 atmospheric pressure (Pi) = 1.01 * 10$^{5}$ Pa

Elevation (h) = 86m

gravity (g) = 9.8 m/s2

Density of air P = 1.225 kg/m3

Therefore pressure at bad water Pb = Pi + Pgh

Pb = (1.01 * 10$^{5}$) + (1.225 * 9.8 * 86)

Pb = (1.01 * 10$^{5}$) + 1032.43 = 102032 Pa

hence:

Pb = 102032 /1.01 * 10$^{5}$ = 1.01022 atm