Question

Express these numerals in the expanded form of power 10. (4) a. 5060 b.6079000 2. How many millions are there in 3 crore?(1) 3.What is the greatest number of 6 digits?(1) 4.What is the least number formed by 5 digits 4,1,8,0,7?(1) 5. Simplify: a. 18 - 7 + 9* 48/6 - 5 (1) b. 72/ 12 [ 180/4{10 +(15 - 45 /9*2)}]

Answer 1

Answer:

$a)\ 5.06 * 10\³$

$b)\ 6.079 * 10^6$

$c)\ 3\ crore = 30\ million$

$d)\ 999999$

$e)\ 10478$

$f)\ 78$

$g)\ 2730$

Step-by-step explanation:

Solving (a): 5060 as a power of 10

We simply move the decimal between 5 and 6. The number of zeros to move backward is 4.

So,

$5 0 6 0 = 5.06 * 10^3$

Solving (b): 6079000 as a power of 10

We simply move the decimal between 6 and 0. The number of zeros to move backward is 4.

So,

$6079000 = 6.079 * 10^6$

Solving (c): 3 crore to millions

$1\ crore = 10\ million$

Multiply by 3

$3\ crore = 30\ million$

Solving (d): The greatest 6 digits

The greatest unit digit is 9. So, we simply write out 9 in 6 places

$Greatest= 99999$

Solving (e): The least 5-digit formed from 4,1,8,0,7

To do this, we start the number from the smallest non-zero digit.

The remaining 4 digits will then be in an increasing order

So, we have:

$Least = 10478$

Solving (f):

$18 - 7 + 9 * \frac{48}{6} - 5$

Using BODMAS

Evaluate the division, first

$18 - 7 + 9 * 8 - 5$

Then multiplication

$18 - 7 + 72 - 5$

Add up the remaining digits

$78$

Solving (g): This question is not clear.

I will assume the expression is:

$\frac{72}{ 12}* [ \frac{180}{4}*{10 +(15 - \frac{45}{9}*2)}]$

Evaluate all divisions

$6* [ 45*{10 +(15 - 5*2)}]$

Solve the multiplication in brackets

$6* [ 45*{10 +(15 - 10)}]$

Remove the inner bracket

$6* [ 45*{10 +5}]$

Evaluate 45 * 10

$6* [ 450 +5}]$

Remove the bracket

$6* 455$

Multiply

$2730$