Question

I want to create water out of 45.4 Liters of Oxygen at STP. How much water will I produce?
STP: Standard Temperature and Pressure
72g H2O
36g H20
9g H20
18g H20

Answer 1

Answer:

72.96 of water produce by 45.4 L of oxygen at STP.

Explanation:

$H_2+\frac{1}{2}O_2\rightarrow H_2O$

1 mole of oxygen=22.4 L at STP

$\frac{1}{2}$\mole of oxygen=22.4/2=11.2 L

11.2 L of oxygen required to produce water=1 mole

1 L of oxygen required to produce water=1/11.2 mole

45.4 L of oxygen required to produce water=$\frac{1}{11.2}\times 45.4$

45.4 L of oxygen required to produce water=$\frac{45.4}{11.2}$moles

1 mole of water=18 g

$\frac{45.4}{11.2}$moles of water=$18\times \frac{45.4}{11.2}$

$\frac{45.4}{11.2}$moles of water=72.96 g

Hence, 72.96 of water produce by 45.4 L of oxygen at STP.