Question

Juanita ran one mile around her school track in six minutes. What is
her average speed, and what is the magnitude of her average velocity?
10 mph, 0 mph
6 mph, 0 mph
6 mph, 6 mph
10 mph, 10 mph

Answer 1

Answer:

The correct option is a) 10 mph, 0 mph.

Explanation:

1. The average speed (S) is a magnitude given by:

$S = \frac{D}{T}$  

Where:

D: is the total distance = 1 mi

T: is the total time = 6 min

$S = \frac{D}{T} = \frac{1 mi}{6 min}*\frac{60 min}{1 h} = 10 mph$

Hence, the average speed is 10 mph.

2. The average velocity is a vector:

$V = \frac{\Delta d}{\Delta t} = \frac{d_{f} - d_{i}}{t_{f} - t_{i}}$

Where:

$d_{f}$: is the final distance                                    

$d_{i}$: is the initial distance  

$t_{f}$: is the final time                

$t_{i}$: is the initial time

Since Juanita ran one mile around her school track, the final position is the same that the initial position, so the magnitude of the average velocity is zero.                                               

Therefore, the correct option is a) 10 mph, 0 mph.

I hope it helps you!