Answer:
0.0158 = 1.58% probability that all of them are under 18.
Step-by-step explanation:
Probability of independent events:
If three events, A, B and C are independent, the probability of all happening is the multiplication of the probabilities of each happening, that is:
[tex]P(A \cap B \cap C) = P(A)P(B)P(C)[/tex]
The percentage of people under the age of 18 was 23.5% in New York City, 25.8% in Chicago, and 26% in Los Angeles.
This means that [tex]P(A) = 0.235, P(B) = 0.258, P(C) = 0.26[/tex]
If one person is selected from each city, what is the probability that all of them are under 18?
Since the three people are independent:
[tex]P(A \cap B \cap C) = 0.235*0.258*0.26 = 0.0158[/tex]
0.0158 = 1.58% probability that all of them are under 18.
