Question

what is the maximum value of y=-x^2-x+6 ?

Answer 1

Answer:

${ \tt{y = - {x}^{2} - x + 6 }} \\ { \tt{ \frac{dy}{dx} = - 2x - 1}} \\ f {}^{'} (x) = - 2x - 1 \\ f {}^{'}(1) = - 2 - 1 \\ = - 3$