Question

At what frequency would an inductor of inductance 0.8H have a reactance of 12000^?​

Answer 1

Explanation:

The inductive reactance $X_L$ is given by

$X_L = \omega L = 2 \pi fL$

Solving for f, we get

$f = \dfrac{X_L}{2 \pi L} = \dfrac{12000\:\text{ ohms}}{2\pi (0.8\:H)}$

$\:\:\:\:\:\:\:= 2387.3\:\text{Hz}$