Question

Determine the equation of the circle in standard form:
x^2+y^2+4x+6y-36=0

Answer 1

Answer:

2. (x+2)²+(y+3)²=49

Step-by-step explanation:

it is possible to re-write the given equation:

x²+4x+4+y²+6y+9-49=0;

(x+2)²+(y+3)²-49=0;

(x+2)²+(y+3)²=7².