Question

Can you help me with this?
(I will give one of you brainliest)

Answer 1

Answer:

1) $\sqrt{9}$ and $\sqrt{16}$ (between 3 and 4)

Explanation: $\sqrt{9}$ and $\sqrt{16}$ are the closest WHOLE squares root to $\sqrt{12}$; any other square roots wouldn't give us a whole number, or they're farther away from

2) $-\sqrt{144}$ and $-\sqrt{169}$ (between -(12) and -(13))

3) $-\sqrt{36}$ and $-\sqrt{49}$ (between -(6) and -(7))

Answer 2

Answer:

see explanation

Step-by-step explanation:

Consider perfect squares on either side of the radicand

(a)

9 < 12 < 16 , then

$\sqrt{9}$ < $\sqrt{12}$ < $\sqrt{16}$ , so

3 < $\sqrt{12}$ < 4

(b)

- 144 <  - $\sqrt{158}$ < - 169

- $\sqrt{144}$ < - $\sqrt{158}$ < - $\sqrt{169}$ , s0

- 12 < - $\sqrt{158}$ < - 13

(c)

- 36 < - $\sqrt{40}$ < - $\sqrt{49}$ , so

- 6 < - $\sqrt{40}$ < - 7