Question

A bottling company marks a 0 for every bottle that comes out correct and a 1 for every defective bottle. Estimate the probability that the next bottle is defective

Answer 1

Answer:

See Explanation

Step-by-step explanation:

Given

$0 \to$ Correct

$1 \to$ Defective

Required

The probability that the next is defective

The question is incomplete because the list of bottles that came out is not given.

However, the formula to use is:

$Pr = Num ber\ o f\ d e f e c t i v e \div T o t a l\ b o t t l e s$

Take for instance, the following outcomes:

$0\ 1\ 0\ 0\ 0\ 1\ 0\ 0\ 1\ 1\ 0\ 0\ 0\ 1$

We have:

$Total = 14$

$D e f e ctive = 9$ --- i.e. the number of 0's

So, the probability is:

$Pr = 9 \div 14$

$Pr = 0.643$

Answer 2

Answer:

1/20

Step-by-step explanation:

000000000000100000

It is asking the probability of a defective bottle

there is one defective bottle out of 20