Answer:
[tex]Domain = (-\infty, \infty)[/tex]
[tex]Range = (-\infty, 4][/tex]
Increasing interval is: [tex](-\infty, 0)[/tex]
Decreasing interval is: [tex](0, \infty)[/tex]
Constant at no interval
Step-by-step explanation:
Given
See attachment for graph
Solving (a): The domain
From, the attached graph, we have:
[tex]y = -x^2 + 4[/tex]
The degree of the polynomial (i.e 2) is even.
Hence, the domain is the set of all real numbers, i.e.
[tex]Domain = (-\infty, \infty)[/tex]
Solving (b): The range
The curve of [tex]y = -x^2 + 4[/tex] opens downward, and the maximum is:
[tex]y_{max} = 4[/tex]
This means that the minimum is:
[tex]y_{mi n} = -\infty[/tex]
Hence, the range of the set is:
[tex]Range = (-\infty, 4][/tex]
Solving (c): Interval where the function increases/decreases/constant
In (a), we have:
[tex]Domain = (-\infty, \infty)[/tex]
Split to 2 (at vertex x = 0)
[tex](-\infty, 0)[/tex] and [tex](0, \infty)[/tex]
So:
The increasing interval is: [tex](-\infty, 0)[/tex]
The decreasing interval is: [tex](0, \infty)[/tex]
The function has a tangent at [tex]x = 0[/tex] but at no interval, was the function constant