Given:
The given equation is:
[tex]\dfrac{\sqrt{2x}}{\sqrt{x-1}}=2[/tex]
To find:
The solution for the given equation.
Solution:
We have,
[tex]\dfrac{\sqrt{2x}}{\sqrt{x-1}}=2[/tex]
On simplification, we get
[tex]\sqrt{2x}=2\sqrt{x-1}[/tex]
Squaring both sides, we get
[tex]2x=4(x-1)[/tex]
[tex]2x=4x-4[/tex]
[tex]2x-4x=-4[/tex]
[tex]-2x=-4[/tex]
Divide both sides by -2.
[tex]x=\dfrac{-4}{-2}[/tex]
[tex]x=2[/tex]
Therefore, the correct option is B.
