Question

Given that the area of a triangle ABC is 4.5 m², a=4, b=3, find two possible measures for angle C. Round your answer to the nearest tenth

Answer 1

Answer:

$C = 48.6$

Step-by-step explanation:

Given

$Area= 4.5m^2$

$a =4$

$b = 3$

Required

Find angle C

The area of the triangle will be calculated using:

$Area = \frac{1}{2}ab \sin C$

So, we have:

$4.5= \frac{1}{2} * 4 * 3 * \sin C$

$4.5= 6 * \sin C$

Divide both sides by 6

$0.75= \sin C$

Take arc sin of both sides

$\sin^{-1}(0.75)= C$

$48.6 = C$

$C = 48.6$