Question

g to generate electricity, solar panels typically absorb visible light. How many photons of light with a frequency of 5045x10 14 hz does a solar panel absorb to create 360 kj

Answer 1

Answer:

the number of photons absorbed by the solar panel is 1.08 x 10²¹

Explanation:

Given;

frequency of each photon absorbed, f = 5045 x 10¹⁴ Hz

energy to be created by the solar panel, E = 360 kJ = 360,000 J

The energy of each photon absorbed is calculated as;

$E_{photon} = hf\\\\where;\\\\h \ is \ Planck's \ constant = 6.626 \times 10^{-34} \ Js\\\\E_{photon} = (6.626 \times 10^{-34} )(5045 \times 10^{14})\\\\E_{photon} = 3.343 \times 10^{-16} \ J$

let the number of photons absorbed = n

$n(E_{photon}) = 360,000 \ J\\\\n = \frac{360,000 \ J}{3.343 \times 10^{-16} \ J} \\\\n = 1.08 \times 10^{21} \ photons$

Therefore, the number of photons absorbed by the solar panel is 1.08 x 10²¹