Question

A student is trying to calculate his semester average. He knows that his test average is an 80, his quiz average is a 72, homework is a 90, and classwork is a 93. If tests and quizzes are worth 30% each, and homework and classwork are worth 20% of his overall average, what is his average? Round to the nearest tenth.

What is the mean?

Answer 1

You have to multiply and divide the 20% time the 30

Answer 2

As per linear equation, the average of the student is 82.2.

The mean is 83.75.

What is a linear equation?

A linear equation is an equation that contains one or multiple variable with the highest power of the variable is one.

The student got test average of 80, his quiz average of 72, homework of 90, and classwork of 93.

Test is worth of 30%.

Therefore, the weightage of test is

= 80 × 30%

= 24

Quiz is worth of 30%.

Therefore, the weightage of quiz is

= 72 × 30%

= 21.6

Homework is worth of 20%.

Therefore, the weightage of homework is

= 90 × 20%

= 18

Classwork is worth of 20%.

Therefore, the weightage of classwork is

= 93 × 20%

= 18.6

Therefore, the average of the student is

= (24 + 21.6 + 18 + 18.6)

= 82.2

Now, the mean is

= (80 + 72 + 90 + 93)/4

= 83.75

Learn more about the mean of a data set here: brainly.com/question/24245170

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