Question

What is the equation, in the point-slope form, of the line that is parallel to the given and passes through the point (-1,-1)?

Answer 1

Answer:

y + 1 = 3(x+ 1)

Step-by-step explanation:

(2,3) , (0 ,-3)

Slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

         $= \frac{-3-3}{0-2}\\\\=\frac{-6}{-2}\\\\= 3$

m = 3

Parallel lines have same slope.

m = 3; (-1 , -1)

y -y1 = m (x -x1)

y -[-1] = 3(x -[-1])

y + 1 = 3(x+ 1)

Answer 2

Answer:

D. y+1=3(x+1)