Answer:
Neither answer so far is correct. Assuming you are starting with a class B address, you have 10 bits for subnets. 2^10 is 1024. So 1024 subnets are available.
Each subnet will have 6 bits for hosts. 2^6 = 64. We subtract 2 for the first and last address in the subnet, so 62 host addresses are available per subnet.
Explanation:
there is the example
with detail in image
