Answer:
[tex]here \: is \: your \: solution : - \\ \\ here \: is \: a \: right \: traingle \: with \\ \\ base \: = 52 \: units \\ \\ hypotenuse \: = 65 \: units \\ \\ perpendicular \: = {?} \\ \\ we \: need \: to \: find \: perpendicular \\ \\ by \: using \: pythagorus \: theorem : - \\ \\ perpendicular ^{2} \: = base ^{2} + perpendicular ^{2} \: \\ \\ perpendicular^{2} \: = 65 {}^{2} - 52 {}^{2} \\ \\ perpendicular {}^{2} = (4225 - 2704) \\ \\ perpendicular {}^{2} = 1521 \\ \\ perpendicular = \sqrt{1521} \\ \\ perpendicular = 39 \: units \: \\ \\ hope \: it \: helps \: you \: [/tex]
