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Answer:
F ∪ H = [2, ∞)
F ∩ H = (6, ∞)
Step-by-step explanation:
Graphs of the two sets are shown in the attachment. Set F is shown in red; set H is shown in blue. The solid dot means the point is included in the set, equivalent to a square bracket in interval notation. The open dot means the point is not included in the set, equivalent to a round bracket (parenthesis) in interval notation.
F ∪ H
The union of two sets is the set that contains elements that are members of either set. Here, set F includes all of the elements of set H, so the union of the to sets is simply set F.
F∪H = F = [2, ∞)
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F ∩ H
The intersection of two sets is the set of elements that are common to both sets. Here, every element of set H is also an element of set F, but not vice versa. So, the intersection of the sets is equivalent to set H.
F∩H = H = (6, ∞)
