Respuesta :

Answer:

[tex]a=0.33\ m/s^2[/tex]

Explanation:

For washer 2,

v₁ = 0.13 m/s

v₂ = 0.36 m/s

t₁ = 1.92

t₂ = 2.61

We need to find the acceleration of waster 2.

[tex]a=\dfrac{v_2-v_1}{t_2-t_1}\\\\a=\dfrac{0.36-0.13}{2.61-1.92}\\\\a=\dfrac{0.23}{0.69}\\\\a=0.33\ m/s^2[/tex]

So, the acceleration of washer 2 is [tex]0.33\ m/s^2[/tex].

Answer:

.33

Explanation:

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