Someone please help :')

Answer:
C. [tex]y+4=-3(x-3)[/tex]
Step-by-step explanation:
The point-slope format is a way to represent the equation of a line. It involves using a point on the line and relating it to the slope in such a way that one can find any point on the line using the equation. One is asked to find the equation of a line in point-slope form. The general format for the point-slope form of a line is the following;
[tex]y-h=m(x-k)[/tex]
Where the point on the line that is being used is ([tex]h,k[/tex]). The parameter ([tex]m[/tex]) represents the slope or rate of change in the line. The slope is often referred to as the ([tex]\frac{rise}{run}[/tex]) and can be found using the following formula.
[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Where ([tex]x_1,y_1[/tex]) and ([tex]x_2,y_2[/tex]) are points on the line. As one can see the following points can be found on the line:
[tex](3,-4), (0, 5)[/tex]
Substitute these points into the slope formula and solve for the slope;
[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{(5)-(-4)}{(0)-(3)}[/tex]
= [tex]\frac{5+4}{0-3}\\[/tex]
= [tex]\frac{9}{-3}[/tex]
= [tex]-3[/tex]
Now substitute the slope into the given formula. As per the problem, one is supposed to use the point ([tex]3, -4[/tex]) in the formula.
[tex]y-h=m(x-k)[/tex]
Substitute the slope;
[tex]y-h=-3(x-k)[/tex]
Substitute the point;
[tex]y+4=-3(x-3)[/tex]