The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula P = a Superscript three-halves. If Saturn’s orbital period is 29.5 years, what is its distance from the sun?

Respuesta :

Answer:

9.54731702 astronomical units

Step-by-step explanation:

[tex]P=a^{\frac{3}{2} }[/tex]

Substitute this value in the equation above:

[tex]29.5=a^{\frac{3}{2} }[/tex]

⇒ [tex](29.5)^{\frac{3}{2} } =a[/tex]

⇒ [tex]a=9.54731702[/tex] [tex]astronomical[/tex] [tex]units[/tex]

Hence, its distance from the sun is 9.54731702 astronomical units.

Answer:

its a

Step-by-step explanation:

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