Question

Write the balanced dissociation equation for solid sulfur difluoride in aqueous solution. If it does not dissociate, simply write only NR.

Answer 1

Answer:

SF2(aq) → S²⁺(aq) + 2F-(aq)

Explanation:

The sulfur difluoride, SF2, dissolves in water because the differences in electronegativities are considerable (3.98 for Fluorine and 2.58 for S) doing the F-S bond polar. As water is a polar solvent will dissolve the SF2 as follows:

SF2(aq) → S²⁺(aq) + 2F-(aq)

As Fluorine has a > electronegativity than S, the Fluorine will be negative and S will be positive. Also, all halogen ions has a charge of -1.