I need help solving my homework problem , can somebody help me please . This class is physics two . My question is “ where the potential difference across ab is 49.5 V “ ?

Explanation:
a) [tex]Q_{Total} = C_{eq}V = (3.5\:\mu \text{F})(49.5V) = 1.73×10^{-4}\:\text{C}[/tex]
b) The individual capacitors in series circuit carry the same amount of charge as the [tex]Q_{Total}[/tex] so
[tex]Q_{10} = Q_{Total} = 1.73×10^{-4}\:\text{C}[/tex]
c) Likewise, [tex]C_9[/tex] will carry the same amount of charge as [tex]C_{10}[/tex]