Answer:
31.99 g O2
Explanation:
Any gas at STP has a molar volume of 22.4 L/mol. This may be an amount you want to memorize.
(given volume) * (molar volume)= moles of O2
[tex]22.4 L * \frac{1 mol}{22.4 L}= 1 mol O2[/tex]
Now we can convert moles of O2 to grams using the molar mass of O2.
(moles of O2) * (molar mass of O2)= grams of O2
[tex]1 mol * \frac{31.99 g}{1 mol} = 31.99g[/tex]
The statement of the mass of O2 is "31.99 g."
A substance is something to do with mass that takes up space. The mass of a compound is the total amount of atoms present in grams that make up a molecule. The grams is the unit of mass
While the preceding method may have been utilised, PV = nRT is not required when the system is at STP. Simply put, 1 mole of an ideal gas equals 22.4 litres at STP.
Number of moles in 22.4 L of O2 at STP,
= (given volume) * (molar volume)
[tex]=\;22.4\;L*\frac{1\;mol}{22.4\;L}[/tex]
= 1 mol O2
Now, mass of O2 at STP comes out to be,
= (moles of O2) * (molar mass of O2)
[tex]=\;1\;mol\;O2\;*\frac{31.99\;g}{1\; mol\;O2}[/tex]
= 31.99 g
Hence the correct answer is 31.99 g.
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