Question

A 0.413 kg block requires 1.09 N
of force to overcome static
friction. What is the coefficient
of static friction?
(No unit)

Answer 1

Answer:

Explanation:

The equation for this is

f = μ$F_n$ where f is the frictional force the block needs to overcome, μ is the coefficient of static friction, and $F_n = w=mg$ (that means that the normal force is the same as the weight of the block which has an equation of weight = mass times the pull of gravity). Filling in:

1.09 = μ(.413)(9.8) and

μ = $\frac{1.09}{(.413)(9.8)}$ so

μ = .27

Answer 2

Answer:

.27

Explanation:

I'm on Acellus as well and its the right answer