Answer: Both x and y are [tex]\frac{\sqrt{2}}{2}[/tex] which is the same as [tex]\frac{1}{\sqrt{2}}[/tex]
In other words, the point [tex]\left( \frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2} \right)[/tex] is on the unit circle for the angle pi/4 radians. This point is equivalent to [tex]\left( \frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}}\right)[/tex]
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Explanation:
The angle pi/4 radians is equivalent to 45 degrees. Draw out a 45-45-90 triangle with hypotenuse 1, and you'll find the congruent legs are each [tex]\frac{1}{\sqrt{2}}[/tex] units long (apply the pythagorean theorem). If you apply the sine and cosine ratios, you'll get the answer shown above.
Recall that
and also
The pythagorean theorem is a^2+b^2 = c^2.