Respuesta :

Answer: Both x and y are [tex]\frac{\sqrt{2}}{2}[/tex] which is the same as [tex]\frac{1}{\sqrt{2}}[/tex]

In other words, the point [tex]\left( \frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2} \right)[/tex] is on the unit circle for the angle pi/4 radians. This point is equivalent to [tex]\left( \frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}}\right)[/tex]

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Explanation:

The angle pi/4 radians is equivalent to 45 degrees. Draw out a 45-45-90 triangle with hypotenuse 1, and you'll find the congruent legs are each [tex]\frac{1}{\sqrt{2}}[/tex] units long (apply the pythagorean theorem). If you apply the sine and cosine ratios, you'll get the answer shown above.

Recall that

  • x = cos(theta)
  • y = sin(theta)

and also

  • cos = adjacent/hypotenuse
  • sin = opposite/hypotenuse

The pythagorean theorem is a^2+b^2 = c^2.

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