Given:
The equation is:
[tex](5+x)(5-x)=7[/tex]
To find:
The value of A, B and C for the equation's general form.
Solution:
We have,
[tex](5+x)(5-x)=7[/tex]
Using distribution property, we get
[tex](5)(5)+(5)(-x)+(x)(5)+(x)(-x)=7[/tex]
[tex]25-5x+5x-x^2=7[/tex]
[tex]25-x^2=7[/tex]
Taking all terms on one side, we get
[tex]25-x^2-7=0[/tex]
[tex]-x^2+18=0[/tex]
[tex]-(x^2-18)=0[/tex]
[tex]x^2-18=0[/tex]
On comparing this equation with the general form of a quadratic equation [tex]Ax^2+Bx+C=0[/tex], we get
[tex]A=1[/tex]
[tex]B=0[/tex]
[tex]C=-18[/tex]
Therefore, the correct option is 1.