contestada

If you produce 35.7 grams of sodium chloride how many molecules of Chlorine gas were
needed?
2Na + Cl2 --> 2NaCl
(PLS HELP)

Respuesta :

Answer: [tex]7.36\times 10^{23}[/tex] number of molecules of chlorine gas are needed.

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Given mass of sodium chloride = 35.7 g

Molar mass of sodium chloride = 58.44 g/mol

Plugging values in equation 1:

[tex]\text{Moles of sodium chloride}=\frac{35.7g}{58.44g/mol}=0.611 mol[/tex]

The given chemical equation follows:

[tex]2Na+Cl_2\rightarrow 2NaCl[/tex]

By the stoichiometry of the reaction:

If 1 mole of sodium chloride is produced from 2 moles of chlorine gas

So, 0.611 moles of sodium chloride will be produced from = [tex]\frac{2}{1}\times 0.611=1.222mol[/tex] of chlorine gas

According to the mole concept:

1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of molecules

So, 1.222 moles of chlorine gas will contain = [tex]\frac{6.022\times 10^{23}}{1mol}\times 1.222mol=7.36\times 10^{23}[/tex] number of molecules

Hence, [tex]7.36\times 10^{23}[/tex] number of molecules of chlorine gas is needed.

ACCESS MORE