Respuesta :

Given:

The graph of a quadratic function.

To find:

The equation of the quadratic function in factored form.

Solution:

From the given graph it is clear that the graph of the function intersect the x-axis at point (-3,0) and (2,0).

Since -3 and 2 are the zeros of the function, therefore (x+3) and (x-2) are the factors of the required quadratic function.

Now, the function can be written as:

[tex]f(x)=a(x+3)(x-2)[/tex]             ...(i)

The graph of the function intersect the y-axis at (0,-6). Substituting [tex]x=0,f(x)=-6[/tex] in (i), we get

[tex]-6=a(0+3)(0-2)[/tex]

[tex]-6=a(3)(-2)[/tex]

[tex]-6=-6a[/tex]

[tex]\dfrac{-6}{-6}=a[/tex]

[tex]1=a[/tex]

Substituting [tex]a=1[/tex] in (i), we get

[tex]f(x)=1(x+3)(x-2)[/tex]

Therefore, the required function is [tex]f(x)=1(x+3)(x-2)[/tex].

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