What is the equation, In factored form, of the quadratic function shown in the graph?

Given:
The graph of a quadratic function.
To find:
The equation of the quadratic function in factored form.
Solution:
From the given graph it is clear that the graph of the function intersect the x-axis at point (-3,0) and (2,0).
Since -3 and 2 are the zeros of the function, therefore (x+3) and (x-2) are the factors of the required quadratic function.
Now, the function can be written as:
[tex]f(x)=a(x+3)(x-2)[/tex] ...(i)
The graph of the function intersect the y-axis at (0,-6). Substituting [tex]x=0,f(x)=-6[/tex] in (i), we get
[tex]-6=a(0+3)(0-2)[/tex]
[tex]-6=a(3)(-2)[/tex]
[tex]-6=-6a[/tex]
[tex]\dfrac{-6}{-6}=a[/tex]
[tex]1=a[/tex]
Substituting [tex]a=1[/tex] in (i), we get
[tex]f(x)=1(x+3)(x-2)[/tex]
Therefore, the required function is [tex]f(x)=1(x+3)(x-2)[/tex].