Find the circumference of this circle
using 3 for TT.
C = ?

[tex]{ \bf{ \underbrace{Given}}}[/tex]:
Diameter of the circle "[tex]d[/tex]" = [tex]36[/tex]
Value of [tex]π[/tex] = [tex]3[/tex]
[tex]{ \bf{ \underbrace{To\:find}}}[/tex]:
The circumference "[tex]C[/tex]" of the circle.
[tex]{ \bf{ \underbrace{Solution }}}[/tex]:
[tex]\sf\pink{The\:circumference \:"C"\:of\:the\:circle\:is\:108.}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
We know that,
[tex]\sf\purple{Circumference\:of\:a\:circle \:=\:πd }[/tex]
[tex] = 3 \times 36[/tex]
[tex] = 108[/tex]
Therefore, the circumference of the circle is [tex]108[/tex].
[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]
Answer:
[tex]\Longrightarrow: \boxed{\sf{108}}[/tex]
Step-by-step explanation:
Apply the formula for the circle's circumference.
[tex]\text{Circumference circle formula:}[/tex]
[tex]\Longrightarrow: \sf{C=\pi d}[/tex]
[tex]\Longrightarrow:\sf{C=?}\\\\\Longrightarrow:\sf{\pi =3}\\\\\Longrightarrow:\sf{d=36}[/tex]
Multiply.
[tex]\sf{3*36=\boxed{\sf{108}}[/tex]
I hope this helps! Let me know if you have any questions.