Question

Constants Periodic Table Part A Carla holds a ball 1.5 m above the ground. Daniel, leaning out of a car window, also holds a ball 1.5 mm above the ground. Daniel drives past Carla at 40 mph and, just as he passes her, both release their balls at the same instant.
Whose ball hits the ground first?
The balls will hit the ground simultaneously.
Daniel's.
Carla's The answer can't be determined from the data provided

Answer 1

Answer:

correct answer is c

The balls will hit the ground simultaneously

Explanation:

This is an exercise in kinematics, let's analyze each case separately

Carla. Holds the ball at an initial height y = 1,5m and releases the ball therefore its initial velocity is zero v₀ = 0

          y = y₀ + v₀ t - ½ gt²

          0 = y₀ + 0 - ½ g t²

          t = $\sqrt{\frac{2y_o}{g} }$

Daniel This holds the ball at I = 1.5 m and releases the ball as it passes by Carla, therefore the initial velocity is

horizontal vox = 40 mph

vertical   v_{oy} = 0

           y = y_{oy}I + v_{oy} t - ½ g t²

            0 = y_{oy} + 0 - ½ g t²

            t = $\sqrt{\frac{2 y_o}{g} }$

we can see that they both spend the same time reaching the ground

           t = $\sqrt{2 \ 1.5 / 9.8}$

           t = 0.55 s

The correct answer is c

The balls will hit the ground simultaneously