Answer: 143.48 moles of copper will be produced.
Explanation:
We are given:
Number of particles of copper (I) sulfate = [tex]4.32\times 10^{25}[/tex]
According to the mole concept:
[tex]6.022\times 10^{23}[/tex] number of particles is contained in 1 mole of a compound
So, [tex]4.32\times 10^{25}[/tex] number of particles will be contained in = [tex]\frac{1}{6.022\times 10^{23}}\times 4.32\times 10^{25}=71.74mol[/tex] of copper (I) sulfate
The given chemical equation follows:
[tex]Fe+Cu_2SO_4\rightarrow FeSO_4+2Cu[/tex]
By the stoichiometry of the reaction:
If 1 mole of copper (I) sulfate produces 2 moles of Cu
So, 71.74 moles of copper (I) sulfate will produce = [tex]\frac{2}{1}\times 71.74=143.48mol[/tex] of Cu
Hence, 143.48 moles of copper will be produced.
